Another tough problem solving help? please?

ok my friend need to know a wall of his basement is 32 feet by 8 feet. the wall is to be constructed with masonary blocks that have lenghts of 16 inches and widths of 8 inches. about how many masonary blocks are needed to build the wall?

And please one for me i want to have a circular swimming pool. it will have diameter of 20 feet and depth of 6 feet how much dirt must be removed?? Thanks so much

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5 Responses to Another tough problem solving help? please?

  1. kumorifox says:

    1 foot = 12 inch, so 32 feet = 384 inch and 8 feet = 96 inch, so the entire area of the wall is 36864 square inch.

    A block has an area of 16×8 = 128 square inch. Divide to get the total number of blocks.

    You have to remove a cylinder-shaped amount of sand. The volume of a cylinder is πr²h. The radius is 10 ft and the height 6 ft. Work it from there.

  2. AndrewFM says:

    32 feet = 384 inches (32*12)
    8 feet = 96 inches (8*12)

    384/16 = 24 blocks across
    96/8 = 12 blocks high

    24*12 = 288 mason blocks.

    ——————————————–

    Area of a cylindar: h*(PI*r^2)

    6*(PI*10^2) = 1885 cubic feet of dirt.

  3. Shelza K says:

    swimming pool: radius=10 feet, height= 6feet
    volume=pie*r*r*height
    volume=22/7*10*10*6
    =1885.71 cubic feet of dust

  4. njbratbrit says:

    first i converted everything to inches
    wall area = l *w = 384 * 96 = 36864 inches
    block area = l * w = 16 * 8 = 128
    38864 divided by 128 = 303.625
    About 304 blocks are needed

    Volume of a cylinder = 2*pi*r^2*h = (2)(pi)(1/2*20)^2(6)= 3770 cubic feet of dirt

  5. Amit S says:

    your friend needs (32*12)*(8*12)/(16*8) = 288

    you need to take out 3.14*(10^2)*6 =1884 cubic feet

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