ok my friend need to know a wall of his basement is 32 feet by 8 feet. the wall is to be constructed with masonary blocks that have lenghts of 16 inches and widths of 8 inches. about how many masonary blocks are needed to build the wall?

And please one for me i want to have a circular swimming pool. it will have diameter of 20 feet and depth of 6 feet how much dirt must be removed?? Thanks so much

1 foot = 12 inch, so 32 feet = 384 inch and 8 feet = 96 inch, so the entire area of the wall is 36864 square inch.

A block has an area of 16×8 = 128 square inch. Divide to get the total number of blocks.

You have to remove a cylinder-shaped amount of sand. The volume of a cylinder is πr²h. The radius is 10 ft and the height 6 ft. Work it from there.

32 feet = 384 inches (32*12)

8 feet = 96 inches (8*12)

384/16 = 24 blocks across

96/8 = 12 blocks high

24*12 = 288 mason blocks.

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Area of a cylindar: h*(PI*r^2)

6*(PI*10^2) = 1885 cubic feet of dirt.

swimming pool: radius=10 feet, height= 6feet

volume=pie*r*r*height

volume=22/7*10*10*6

=1885.71 cubic feet of dust

first i converted everything to inches

wall area = l *w = 384 * 96 = 36864 inches

block area = l * w = 16 * 8 = 128

38864 divided by 128 = 303.625

About 304 blocks are needed

Volume of a cylinder = 2*pi*r^2*h = (2)(pi)(1/2*20)^2(6)= 3770 cubic feet of dirt

your friend needs (32*12)*(8*12)/(16*8) = 288

you need to take out 3.14*(10^2)*6 =1884 cubic feet